Divisible by 3 and 5

/*
 * Problem : Check if a number is divisible by 3, by 5, by both or by neither.
 * Input   : One integer.
 * Output  : One of four messages.
 * Approach: Use the remainder operator twice.
 * Time    : O(1)
 * Space   : O(1)
 * Java    : 8 or newer.
 */
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        int number = new Scanner(System.in).nextInt();

        // Step 1: A number is divisible by 3 when the remainder of the division by 3 is 0. Same for 5.
        boolean by3 = number % 3 == 0;
        boolean by5 = number % 5 == 0;

        // Step 2: Check the "both" case first. Otherwise the single cases would also match.
        if (by3 && by5) {
            System.out.println("Divisible by both 3 and 5");
        } else if (by3) {
            System.out.println("Divisible by 3 only");
        } else if (by5) {
            System.out.println("Divisible by 5 only");
        } else {
            System.out.println("Divisible by neither");
        }
    }
}