Find Duplicate Values
Problem
Print all values that appear more than once, each one time, in ascending order. Print none if there are no duplicates.
Constraints
- 1 <= n <= 10^5
Examples
Input
8 4 3 2 7 8 2 3 1
Output
2 3
Solutions
A frequency map gives the answer in one pass. A value is a duplicate when its count is above 1.
/*
* Problem : Process an array.
* Input : n, then n integers.
* Output : The duplicate values.
* Approach: Count the values.
* Time : O(n log n)
* Space : O(n)
* Java : 8 or newer.
*/
import java.util.Scanner;
public class Main {
// This method solves the task. It receives the input and returns the answer.
static String solve(int[] a) {
// Step 1: Count each value in a TreeMap (sorted by key).
java.util.TreeMap<Integer, Integer> counts = new java.util.TreeMap<>();
for (int value : a) {
counts.merge(value, 1, Integer::sum);
}
// Step 2: Collect the values with a count above 1.
StringBuilder text = new StringBuilder();
for (java.util.Map.Entry<Integer, Integer> entry : counts.entrySet()) {
if (entry.getValue() > 1) {
text.append(text.length() == 0 ? "" : " ").append(entry.getKey());
}
}
return text.length() == 0 ? "none" : text.toString();
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int size = scanner.nextInt();
int[] a = new int[size];
for (int i = 0; i < size; i++) {
a[i] = scanner.nextInt();
}
System.out.println(solve(a));
}
}
Hints (1)
- How many times must a value appear to be a duplicate?