Insertion Sort
Problem
Read an array and print it sorted in ascending order. Use insertion sort.
Constraints
- 1 <= n <= 2000
Examples
Input
6 5 2 9 1 5 6
Output
1 2 5 5 6 9
Solutions
This is how many people sort playing cards in the hand. It is very fast on nearly sorted data (O(n)).
/*
* Problem : Sort an array in ascending order.
* Input : n, then n integers.
* Output : The sorted array.
* Approach: Insert into the sorted part.
* Time : O(n^2)
* Space : O(1)
* Java : 8 or newer.
*/
import java.util.Scanner;
import java.util.Arrays;
import java.util.stream.Collectors;
public class Main {
// This method solves the task. It receives the input and returns the answer.
static int[] solve(int[] a) {
// Step 1: The part to the left of index i is already sorted. The first element alone is sorted.
for (int i = 1; i < a.length; i++) {
// Step 2: Take the next value. It must be inserted into the sorted part.
int value = a[i];
int j = i - 1;
// Step 3: Shift bigger values one place to the right.
while (j >= 0 && a[j] > value) {
a[j + 1] = a[j];
j--;
}
// Step 4: Put the value in the free place.
a[j + 1] = value;
}
return a;
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int size = scanner.nextInt();
int[] a = new int[size];
for (int i = 0; i < size; i++) {
a[i] = scanner.nextInt();
}
System.out.println(Arrays.stream(solve(a)).mapToObj(String::valueOf).collect(Collectors.joining(" ")));
}
}
Hints (1)
- What happens to the bigger values while you insert?