Kth Largest Element
Problem
Read an array and a number k. Print the k-th largest element when the array is sorted in descending order (equal values count separately). Example: in 3 2 1 5 6 4 the 2nd largest is 5.
Constraints
- 1 <= k <= n <= 10^5
Examples
Input
6 3 2 1 5 6 4 2
Output
5
Solutions
After sorting, the position of the answer is known. It is easy and takes O(n log n) time. A heap of size k can do it in O(n log k).
/*
* Problem : Process an array and a number k.
* Input : n, then n integers, then k.
* Output : The k-th largest.
* Approach: Sort the array.
* Time : O(n log n)
* Space : O(n)
* Java : 8 or newer.
*/
import java.util.Scanner;
public class Main {
// This method solves the task. It receives the input and returns the answer.
static int solve(int[] a, int k) {
// Step 1: Copy the array, so the input stays unchanged.
int[] sorted = a.clone();
// Step 2: Sort in ascending order.
java.util.Arrays.sort(sorted);
// Step 3: The k-th largest is the k-th element from the end.
return sorted[sorted.length - k];
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int size = scanner.nextInt();
int[] a = new int[size];
for (int i = 0; i < size; i++) {
a[i] = scanner.nextInt();
}
int k = scanner.nextInt();
System.out.println(solve(a, k));
}
}
Hints (1)
- Which index is the k-th element from the end?