Combine Predicates (and, or)

/*
 * Problem : Filter with a rule.
 * Input   : n, array, k.
 * Output  : The kept numbers.
 * Approach: Combine predicates.
 * Time    : O(n)
 * Space   : O(n)
 * Java    : 8 or newer.
 */
import java.util.Scanner;
import java.util.Arrays;
import java.util.stream.Collectors;

public class Main {
    // This method solves the task. It receives the input and returns the answer.
    static int[] solve(int[] a, int k) {
        // Step 1: Small predicates, each with one job. Predicate<Integer> is a function that gives true or false.
        java.util.function.Predicate<Integer> isEven = value -> value % 2 == 0;
        java.util.function.Predicate<Integer> isGreater = value -> value > k;
        java.util.function.Predicate<Integer> isMultipleOfFive = value -> value % 5 == 0;
        // Step 2: Combine them. and() and or() give new predicates, and the old ones stay unchanged.
        java.util.function.Predicate<Integer> keep = isEven.and(isGreater).or(isMultipleOfFive);
        // Step 3: Filter the numbers with the combined predicate.
        return java.util.Arrays.stream(a).boxed().filter(keep).mapToInt(Integer::intValue).toArray();
    }

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int size = scanner.nextInt();
        int[] a = new int[size];
        for (int i = 0; i < size; i++) {
            a[i] = scanner.nextInt();
        }
        int k = scanner.nextInt();
        System.out.println(Arrays.stream(solve(a, k)).mapToObj(String::valueOf).collect(Collectors.joining(" ")));
    }
}