CodingGyan

Rectangle Area and Perimeter

easy Programming Basics

Problem

The length and width of a rectangle are whole numbers. Print its area and its perimeter separated by a space. For 3 and 4 the area is 12 and the perimeter is 14.

Constraints

  • 1 <= length, width <= 10^5

Examples

Input

3 4

Output

12 14

Solutions

Best approachTime O(1)Space O(1)

Both answers come from one-line formulas, so the code is short. We join the two numbers into one output line.

Same code works in Java810172125Basic features only, so nothing changes between versions.
/*
 * Problem : Rectangle.
 * Input   : Length and width.
 * Output  : Area and perimeter.
 * Approach: Formulas.
 * Time    : O(1)
 * Space   : O(1)
 * Java    : 8 or newer.
 */
import java.util.Scanner;

public class Main {
    // This method solves the task. It receives the input and returns the answer.
    static String solve(long a, long b) {
        // Step 1: Area is length times width. Perimeter is twice the sum of the two sides.
        long area = a * b;
        long perimeter = 2 * (a + b);
        return area + " " + perimeter;
    }

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        long a = scanner.nextLong();
        long b = scanner.nextLong();
        System.out.println(solve(a, b));
    }
}
Hints (2)
  1. Why is the perimeter twice the sum?
  2. Which numbers can get big?