Rotate a Matrix by 90 Degrees (Clockwise)
Problem
Read a matrix with r rows and c columns. Rotate it by 90 degrees clockwise and print the result (it has c rows and r columns).
Constraints
- 1 <= r, c <= 100
Examples
Input
2 3 1 2 3 4 5 6
Output
4 1 5 2 6 3
Solutions
Rotating clockwise means: the first column (read from the bottom to the top) becomes the first row. It equals a transpose followed by reversing every row.
/*
* Problem : Process a matrix.
* Input : r and c, then r rows of c integers.
* Output : The rotated matrix.
* Approach: Rotation = transpose + reverse rows.
* Time : O(r * c)
* Space : O(r * c)
* Java : 8 or newer.
*/
import java.util.Scanner;
public class Main {
// This method solves the task. It receives the input and returns the answer.
static String[] solve(int[][] m) {
int rows = m.length;
int cols = m[0].length;
String[] lines = new String[cols];
// Step 1: The new row j is the old column j, read from the bottom to the top.
for (int j = 0; j < cols; j++) {
StringBuilder line = new StringBuilder();
// Step 2: Go through the old rows from the last to the first.
for (int i = rows - 1; i >= 0; i--) {
if (i < rows - 1) {
line.append(" ");
}
line.append(m[i][j]);
}
lines[j] = line.toString();
}
return lines;
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int rows = scanner.nextInt();
int cols = scanner.nextInt();
int[][] m = new int[rows][cols];
for (int i = 0; i < rows; i++) {
for (int j = 0; j < cols; j++) {
m[i][j] = scanner.nextInt();
}
}
System.out.println(String.join("\n", solve(m)));
}
}
Hints (1)
- Which old column becomes the first row?